(3x^3-0x^2-12x)/(2x^2-10x+12)

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Solution for (3x^3-0x^2-12x)/(2x^2-10x+12) equation:


D( x )

2*x^2-(10*x)+12 = 0

2*x^2-(10*x)+12 = 0

2*x^2-(10*x)+12 = 0

2*x^2-10*x+12 = 0

2*x^2-10*x+12 = 0

DELTA = (-10)^2-(2*4*12)

DELTA = 4

DELTA > 0

x = (4^(1/2)+10)/(2*2) or x = (10-4^(1/2))/(2*2)

x = 3 or x = 2

x in (-oo:2) U (2:3) U (3:+oo)

(3*x^3-(12*x)-(0*x^2))/(2*x^2-(10*x)+12) = 0

(3*x^3-12*x)/(2*x^2-10*x+12) = 0

3*x^3-12*x = 0

3*x*(x^2-4) = 0

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

3*x*(x-2)*(x+2) = 0

2*x^2-10*x+12 = 0

2*(x^2-5*x+6) = 0

x^2-5*x+6 = 0

DELTA = (-5)^2-(1*4*6)

DELTA = 1

DELTA > 0

x = (1^(1/2)+5)/(1*2) or x = (5-1^(1/2))/(1*2)

x = 3 or x = 2

2*(x-2)*(x-3) = 0

(3*x*(x-2)*(x+2))/(2*(x-2)*(x-3)) = 0

( 3*x )

3*x = 0 // : 3

x = 0

( x+2 )

x+2 = 0 // - 2

x = -2

( x-2 )

x-2 = 0 // + 2

x = 2

x in { 2}

x in { 0, -2 }

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